UC知道初二分式加减
来源：百度知道 编辑：UC知道 时间：2024/05/16 15:41:00
(1)[（x+1)/(x-1)]-[(4x)/(x^2-1)]
(2)[(x)/(x-3)]-[(x+6)/(x^2-3x)]+1/x
(3)1+[x-(1)/(1-x)]
(4)(x/x-1)+(1/1-x)÷(x/x-1)
(5)(x/x-2)-(x/x+2)*(2-x/x)
请写清步骤。
接下来是一个化简求值。
[x-y+(4xy/x-y)][x-y-(4xy/x+y)]其中x=2 y=1
也请写清步骤，谢谢谢谢谢！！！
(2)[(x)/(x-3)]-[(x+6)/(x^2-3x)]+1/x
(3)1+[x-(1)/(1-x)]
(4)(x/x-1)+(1/1-x)÷(x/x-1)
(5)(x/x-2)-(x/x+2)*(2-x/x)
请写清步骤。
接下来是一个化简求值。
[x-y+(4xy/x-y)][x-y-(4xy/x+y)]其中x=2 y=1
也请写清步骤，谢谢谢谢谢！！！
（1）原式=[(x+1)(x+1)]/(x-1)(x+1)]-[(4x)/(x^2-1)]
=(x^2+2x+1-4x)/(x^2-1)
=(x^2-2x+1)/(x^2-1)
=(x-1)^2/(x+1)(x-1)
=(x-1)/(x+1)
(2)原式=x/(x-3)-(x+6)/(x(x-3))+1/x
=(x^2-(x+6)+x-3)/(x(x-3))
=(x-3)(x+3)/(x(x-3))
=(x+3)/x
=1+3/x
(3)原式=(1-x+x(1-x)-1)/(1-x)
=x^2/(x-1)
(4)原式=x/(1-x)+1/(1-x)*(x-1)/x
=(x^2-1+x)/(x^2-x)
(5)原式=x/(x-2)-(2-x)/(x=2)
=[x^2+2x+(x-2)^2]/(x-2)(x+2)
=2(x-2)(x+1)/(x-2)(x+2)
=2(x+1)/(x+2)
原式=4x*(x+y+x-y)/(x^2-y^2)
=4(x^2)y/(x^2-y^2)
代入数字得到答案为16/5