初二数学【【关于分式约分】】。追加====

(1）1+2x/4x²+4x+1
=(1+2X)/(1+2x)^2
=1/(2x+1)

(2)x+xy/y²-1
=x(1+y)/(y+1)(y-1)
=x/(y-1)

(3)4x-x²/16-x²
=x(4-x)/(4+x)(4-x)
=x/(x+4)

(4)x²-y²/3x²+6xy+3y²
=(x+y)(x-y)/3(x+y)^2
=(x-y)/(x+y)

1)(1+2x)/(2x+1)^2=1/(1+2x)
2)x(1+y)/((y+1)*(y-1))=x/(y-1)
3)x(4-x)/((4-x)*(4+x))=x/(x+4)
4)(x+y)(x-y)/(3(x+y)^2)=(x-y)/(3(x+y))

麻烦自己算一下
好的老师只会指点一下哦

化解

(1）1+2x/4x²+4x+1

=1+2x/(2x+1)²
=1/2x+1

2)x+xy/y²-1

=x(1+y)/(y+1)(y-1)
=x/y-1

(3)4x-x²/16-x²
=x(4-x)/(4+x)(4-x)
=x/4+x

(4)x²-y²/3x²+6xy+3y²

=(x+y)(x-y)/3(x²+2xy+y² )
=(x+y)(x-y)/3(x+y)²
=x-y/3(x+y)

(1）1+2x/(2x+1)^2=1/2x+1
(2)x(1+y)/(1+y)（y-1）=x/y-1
x(4-x)/(4-x)(4+x)=x/4+x
(x-y)(x+y)/3(x+y)^2=x-y/3(x+y)<