问大家几道初中的题

来源:百度知道 编辑:UC知道 时间:2024/06/01 15:13:08
1.已知长方形的周长为20,它两领边的长x ,y是整数,且满足x-y-x2+2xy-y2+2=0,求长方形的面积.

2.已知x-(1/x)=3,求下列代数式的值:1)x2+(1/x2) 2)x2/(x4+x2+1)

1.2x+2y=20
x+y=10
x-y-x2+2xy-y2+2=0
x-y-(x-y)^2+2=0
(x-y-2)(x-y+1)=0
x-y=2或x-y=-1(舍去)
x-y=2,x+y=10解得 x=6,y=4,
长方形的面积=24
2.x-(1/x)=3
x^2-2+1/x^2=9
x^2+1/x^2=11

x2/(x4+x2+1)
=1/(x^2+1/x^2+1)
=1/(11+1)
=1/12

1.2x+2y=20
x+y=10
x-y-x2+2xy-y2+2=0
x-y-(x-y)^2+2=0
(x-y-2)(x-y+1)=0
x-y=2或x-y=-1(舍去)
x-y=2,x+y=10解得 x=6,y=4,
长方形的面积=24
2.x-(1/x)=3
x^2-2+1/x^2=9
x^2+1/x^2=11

x2/(x4+x2+1)
=1/(x^2+1/x^2+1)
=1/(11+1)
=1/12
另外还少了一步
用2.X-(1/X)=x2/-(x4+x2+1)

1
x+y=10 且x y 为整数
与原式联立
或消项 只剩XY
如果题没错相信你能解出来

2
(1)
2x+1/(2x)
=(1/2)*(4x+1/x)
=(1/2)*(4x+x-3)
=(1/2)*(5X-3)

(2)
=1/(2+1+1/2x)
=1/(3+1/x+1/x)
=1/(3+x-3+x-3)
=1/(2x-3)