UC知道解个一元四次方程 在线等
来源：百度知道 编辑：UC知道 时间：2024/06/19 03:37:23
我知道一个答案是1 问题是怎么写
我初三..
5X^4-30X^3+37X^2+24X-36=0
打错了
1不是解啊，
MATLAB求解
>> syms X;
>> solve(5*X^4 - 30*X^3 + 37*X^2 + 12*X - 36,X)
ans =
[ 3/2+1/30*((915*(77327+72*1148790^(1/2))^(1/3)-15*(77327+72*1148790^(1/2))^(2/3)-4335)/(77327+72*1148790^(1/2))^(1/3))^(1/2)+1/30*15^(1/2)*((122*(77327+72*1148790^(1/2))^(1/3)*((915*(77327+72*1148790^(1/2))^(1/3)-15*(77327+72*1148790^(1/2))^(2/3)-4335)/(77327+72*1148790^(1/2))^(1/3))^(1/2)+((915*(77327+72*1148790^(1/2))^(1/3)-15*(77327+72*1148790^(1/2))^(2/3)-4335)/(77327+72*1148790^(1/2))^(1/3))^(1/2)*(77327+72*1148790^(1/2))^(2/3)+289*((915*(77327+72*1148790^(1/2))^(1/3)-15*(77327+72*1148790^(1/2))^(2/3)-4335)/(77327+72*1148790^(1/2))^(1/3))^(1/2)+1080*(77327+72*1148790^(1/2))^(1/3))/(77327+72*1148790^(1/2))^(1/3)/((915*(77327+72*1148790^(1/2))^(1/3)-15*(77327+72*1148790^(1/2))^(2/3)-4335)/(77327+72*1148790^(1/2))^(1/3))^(1/2))^(1/2)]
[ 3/2+1/30*((915*(77327+72*1148790^(1/2))^(1/3)-15*(77327+72*1148790^(1/2))^(2/3)-4335)/(77327+72*1148790^