解答题 速度来!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

∵AB=AC,BC＝BD，AD＝DE＝EB，
∴∠A=∠AED,∠ABC=∠C=∠BDC, ∠EDB=∠EBD
设∠A=x,因∠AED=∠EDB+∠EBD
故∠EDB=∠EBD=x/2
∵∠BDC=∠A+∠ABD=x+x/2=3x/2
∴∠BDC=∠C=∠ABC=3x/2
∵∠A+∠ABC+∠C=180°
∴X+3X/2*2=180
得X=45°
∴∠A的度数是45°

AD=DE=EB
则∠A=∠AED=2∠ABD
BC=BD
则∠C=∠CDB=∠A+∠ABD=3∠A/2
△ABC中
AB=AC
则2∠C+∠A=180
即3∠A+∠A=180

∠A=45

45度