高一数学化简题~急ing~

来源:百度知道 编辑:UC知道 时间:2024/06/13 12:20:57
[sin(540-x)/tan(900-x)]*[1/tan(450-x)*tan(810-x)]*[cos(360-x)/sin(-x)]

sin(540-x)cos(360-x) / tan(900-x)tan(450-x)tan(810-x)sin(-x)

= sin(180-x)cos(-x) / tan(180-x)tan(90-x)tan(90-x)sin(-x)

= - sin(x)cos(x)tan(x)tan(x)cos(180-x) / sin(180-x)sin(x)

= cos^2(x)tan^2(x) / sin(x)

= sinx

[sin(540-x)/tan(900-x)]*[1/tan(450-x)*tan(810-x)]*[cos(360-x)/sin(-x)]

=sin(540-x)cos(360-x) / tan(900-x)tan(450-x)tan(810-x)sin(-x)

= sin(180-x)cos(-x) / tan(180-x)tan(90-x)tan(90-x)sin(-x)

= - sin(x)cos(x)tan(x)tan(x)cos(180-x) / sin(180-x)sin(x)

= cos^2(x)tan^2(x) / sin(x)

= sinx

原式=(sin-x/tan-x)*tanx*cotx*(cosx/sin-x)
=cosx*1*(-tanx)
=sinx
答案是SINX
我的过程比较快