谁能找出这个Java程序的4个错误啊?

来源:百度知道 编辑:UC知道 时间:2024/06/03 20:51:13
public class DNASequence {

private String sequence;

private int numberOfA;

private int numberOfT;

private int numberOfC;

private int numberOfG;

public static void main(String[] args) {

String s = "ATTATCGGGGTAA";
DNASequence dnaSequence = new DNASequence(s);

if ((dnaSequence.getNumberOfA() == 4)
&& (dnaSequence.getNumberOfT() == 4)
&& (dnaSequence.getNumberOfC() == 1)
&& (dnaSequence.getNumberOfG() == 4)) {
System.out.println("Test case 1: get methods passed\n");
} else {
System.out.println("Test case 1: get methods failed !!!\n");
}

if (dnaSequence.twoConsecutive('T')) {
System.out.println("Test case 2: method twoConsecutive passed\n");
} else {
System.out.println(
"Test case 2: method twoConsecutive failed !!!&

没有适当的注释,没有程序的说明.
你的格式写得也不规范.
不如重做的好.
这样的程序是过不了招聘那关的.趁时间还早,赶紧学学代码规范吧....

同学,自己做吧。