小学六年级数学题求解!~~

设1024+512+256+....2+1+1/2+1/4+1/8+......1/512+1/1024=x
2（512+256+.....2+1+1/2+1/4+1/8+.....1/512+1/1024+1/2048)=x
2(1024+512+256+...2+1+1/2+1/4+1/8+....1/512+1/1024+1/2048-1024)=x
2(x+1/2048-1024)=x
2x+1/1024-2048=x
x=2048-1/1024
所以
1024+512+256+....2+1+1/2+1/4+1/8+......1/512+1/1024=2048-1/1024.

1024+512+256+....2+1+1/2+1/4+1/8+......1/512+1/1024
=1/1024+1/512+1/256+....1/2+1+2+4+8+......512+1024
=2048-1/1024
=2047又1024分之1023
A1=1/1024
q=2
An=A1*2^(n-1)
Sn＝a1*(1-q^n)/(1-q)
=1/1024*(2^22-1)
=2048-1/1024
=2047又1024分之1023

小学方法

1024+512+256+....2+1+1/2+1/4+1/8+......1/512+1/1024
=1024+1024(1/2+1/4+1/8+......1/512+1/1024)+(1/2+1/4+1/8+......1/512+1/1024)
=1024+1024*(1-1/2+1/2-1/4+......+1/512-1/1024)+(1-1/2+1/2-1/4+......+1/512-1/1024)
=1024+1024*(1-1/1024)+1-1/1024
=1024+1024-1+1-1/1024
=2048-1/1024
=2047又1023/1024

这是2的N次方相加啊，这应该不是小学