初中两题奥数题,别用太难的解

来源:百度知道 编辑:UC知道 时间:2024/05/05 18:24:31
1.若1/X-1/2Y=1/3 则(2X+3XY-4Y)/(X-3XY-2Y)
2.(X*X+6X+10)/(X*X+6X+9)+(X*X-11)/(X*X-9)-(2X*X+8X+5)/(X*X+4X+3)
建议大家先把“/”写成分数线,把“X*X”写成X的平方 谢谢大家了!

1.解:
x=6y/(2y+3)
原式=-5/11
2.解:
(X*X+6X+10)/(X*X+6X+9)=1+[1/(X*X+6X+9)]
(X*X-11)/(X*X-9)=1-[2/(X*X-9)]
(2X*X+8X+5)/(X*X+4X+3)=2-[1/(X*X+4X+3)]
原式=[1/(X*X+6X+9)]-[2/(X*X-9)]+[1/(X*X+4X+3)]
=1/(X+3)*{[1/(X+3)]-[2/(X-3)]+[1/(X+1)]}
=-(10X+18)/(X^4+4X^3-6X^2-36X-27)

X^4代表X的四次方

1.解:
x=6y/(2y+3)
原式=-5/11
2.解:
(X*X+6X+10)/(X*X+6X+9)=1+[1/(X*X+6X+9)]
(X*X-11)/(X*X-9)=1-[2/(X*X-9)]
(2X*X+8X+5)/(X*X+4X+3)=2-[1/(X*X+4X+3)]
原式=[1/(X*X+6X+9)]-[2/(X*X-9)]+[1/(X*X+4X+3)]
=1/(X+3)*{[1/(X+3)]-[2/(X-3)]+[1/(X+1)]}
=-(10X+18)/(X^4+4X^3-6X^2-36X-27)

X^4代表X的四次方

1. 1/x -1/2y =1/3 则, (2y-x)/2xy=1/3
3(2y-x)=2xy 3xy= 9y-4.5x
算式转化为 (2x + 9y-4.5x-4y)/(x-9y+4.5x-2y)
即 (5y-2.5x)/(5.5x-11y)=2.5(2y-x)/5.5(x-2y)= -5/11

2. 此类题,显然不论x的取值,结果都是确定的。不妨令x=0 代入,结果为5/9
也可以先通分,然后合并同类项,结果一样

1.1/xy(2x+3xy-4y)/[1/xy(x-3xy-2y)]
=.(2/y+3-4/x)/