有关普西函数ψ(z)的计算

来源:百度知道 编辑:UC知道 时间:2024/06/06 00:29:07
已知复数z=x+yi(i^2=-1),试求以下普西函数ψ(z)的值:
ψ(0.25+7.07*i)=?
ψ(0.25+10.51*i)=?
ψ(0.25+12.51*i)=?
ψ(0.25+15.21*i)=?
ψ(0.25+16.47*i)=?
ψ(0.25+18.79*i)=?
ψ(0.25+20.46*i)=?
ψ(0.25+21.66*i)=?
ψ(0.25+24.00*i)=?
ψ(0.25+24.89*i)=?
ψ(0.25+26.49*i)=?
ψ(0.25+28.22*i)=?
ψ(0.25+29.67*i)=?
ψ(0.25+30.42*i)=?
ψ(0.25+32.56*i)=?

ψ(0.25+7.07*i)=1.95565+1.60620*i
ψ(0.25+10.51*i)=2.35223+1.59460*i
ψ(0.25+12.51*i)=2.52646+1.59079*i
ψ(0.25+15.21*i)=2.72191+1.58724*i
ψ(0.25+16.47*i)=2.80150+1.58598*i
ψ(0.25+18.79*i)=2.93330+1.58410*i
ψ(0.25+20.46*i)=3.01845+1.58302*i
ψ(0.25+21.66*i)=3.07545+1.58234*i
ψ(0.25+24.00*i)=3.17804+1.58121*i
ψ(0.25+24.89*i)=3.21445+1.58084*i
ψ(0.25+26.49*i)=3.27675+1.58023*i
ψ(0.25+28.22*i)=3.34002+1.57966*i
ψ(0.25+29.67*i)=3.39012+1.57922*i
ψ(0.25+30.42*i)=3.41509+1.57902*i