用零点分段法解含绝对值的一元一次不等式

x<=-1: -x-1+2x-4<=10 x<=15 x<=-1
x>=2: x+1+2x-4<=10 x<=13/3 2<=x<=13/3
-1<x<2: x+1+4-2x<=10 x>=5
综上: x<=-1
2<=x<=13/3

当x<=-1时:
-x-1+2x-4<=10
解得:x<=15
当x>=2时:
x+1+2x-4<=10
解得:x<=13/3
当-1<x<2时:
x+1+4-2x<=10
解得:x>=5
综上:当...时x...(略)

1、X小于等于-1：-X-1-2X+4小于等于10，-3X+3小于等于10，-3X小于等于7，X大于等于-3分之7，即X大于等于-1
2、X大于-1小于2：X+1-2X+4小于等于10，-X+5小于等于10，X大于等于-5.即X大于-1小于2
3、X大于等于2：X+1+2X-4小于等于10，3X-3小于等于10，X小于等于3分之13，即X大于等于2小于等于3分之13
综上可得X大于等于-1小于等于3分之13

当x<=-1时:
-x-1+2x-4<=10
解得:x<=15
当x>=2时:
x+1+2x-4<=10
解得:x<=13/3
当-1<x<2时:
x+1+4-2x<=10
解得:x>=5
综上:当...时x...(略)

x<=-1: -x-1+2x-4<=10 x<=15 x<=-1
x>=2: x+1+2x-4<=10 x<=13/3 2<=x<=13/3
-1<x<2: x+1+4-2x&l