数学帝，快来！！当m是何实数时,方程2x^+2(3-2m)x+2m+1=0

1.b^-4ac=4(3-2m)^2-8(2m+1)＞0
(3-2m)^2-2(2m+1)＞0
4m^2-12m+9-4m-2>0
4m^2-16m+7>0
(2m-7)(m-1)>0
m>7/2 或 m<1

2.4(3-2m)^2-8(2m+1)=0
(3-2m)^2-2(2m+1)=0
4m^2-12m+9-4m-2=0
4m^2-16m+7=0
(2m-7)(m-1)=0
m=7/2 或 m=1

3.4(3-2m)^2-8(2m+1)＜0
(3-2m)^2-2(2m+1)<0
4m^2-12m+9-4m-2<0
4m^2-16m+7<0
(2m-7)(m-1)<0
1<m<7/2

直接就是判别式大于0，判别式等于0，小于0，三种情况，解出不等式就知道m的范围了。