帮帮忙，初一的数学

m的平方+m=1

m^3+2m^2+2007
=m(m^2+m)+m^2+2007
=m+m^2+2007
=1+2007
=2008

解：因为m²+m-1=0
故：m²=1-m
故：m³+2m²+2007
= m(1-m)+2(1-m)+2007
=m-m²+2-2m+2007
= m-(1-m)+2-2m+2007
=2008

由已知得
m²+m-1=0
m²=1-m
m³+2m²+2007
=m²*m+2m²+2007
= m(1-m)+2(1-m)+2007
=m-m²+2-2m+2007
= m-(1-m)+2-2m+2007
=2008

原式=m(m的平方+m)+m的平方+2007=m+m的平方+2007=1+2007=2008

没抄错吧？！

2010-3m