数学填空1题

规定a*b=-1/2ab,如2*3=-1/2×2×3，则（-2）*[2*（-3）]=（ 3 )

解：2*（－3）
=(-½)×2×(-3)
=(-1)×(-3)
=3
(-2)*3
=(-½)×(-2)×3
=3

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（-2)*[2*(-3)]=-1/2{(-2)*[2*(-3)]}=-1/24.

(-2)*[2*(-3)]
=(-2)*[1/2×2×(-3)]
=(-2)*(-3)
=1/2×(-2)×(-3)
=3