分解因式:(x+y)(x-y)+2x+1
来源:百度知道 编辑:UC知道 时间:2024/06/10 18:00:36
结果写成积的形式
(x+y)(x-y)+2x+1
=x²-y²+2x+1
=(x²+2x+1)-y²
=(x+1)²-y²
=(x+y+1)(x-y+1)
(x+y)(x-y)+2x+1
=x^2-y^2+2x+1
=(x+1)^2-y^2
=(x+1-y)(x+1+y)
(x+y)(x-y)+2x+1
解:原式=x^2-xy+xy-y^2+2x+1
=x^2-y^2+2x+1
=(x^2+2x+1)-y^2
=(x+1)^2-y^2
=[(x+1)+y][(x+1)-y]
=(x+y+1)(x-y+1)
注:x^2是 x平方的意思,这是电脑上的写法
(x+y)(x-y)+2x+1
=x^2-y^2+2x+1
=(x+1)^2-y^2
=(x+1+y)(x+1-y)
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