不等式的解法~高一~！

上学的东西差不多都还给老师了
这个题大概应该这么解，先分解
1<=|x-3|
6>=|x-3|
然后分别解出
X<=2或X>=4
X>=-3或X<=9
则答案为2>=X>=-3或9>=X>=4

1<=|x-3|<=6
即 x-3<=-1 x-3>=1 ===> x<=2 or x>=4
-6<=x-3<=6 ====> -3<=x<=9
由上得 x属于[-3,2]∪[4,9]

first solve the left side: 1<=|x-3|,
remove the absolute sign, x-3<-1 or x-3>1
compound them: x<2 or x>4
then solve the right side: |x-3|<=6,
remove the absolute sign, -6<x-3<6, so as to, -6+3<x and x<6+3
compound them: -3<x<9
combine both of the two parts:
x shoud be x<2 or x>4 and -3<x<9
draw them in the axis, you will see:
-3<x<2 or 4<x<9
this is the final answer

-1≤x-3≤1∪-6≤x-3≤6
-1≤x-3≤1
2≤x≤4