数学题,快来帮帮忙!

来源:百度知道 编辑:UC知道 时间:2024/05/12 05:40:06
因式分解
(1) x(3次方)-7x+6
(2) (ax+by)2次方-(bx-ay)2次方

x(3次方)-7x+6

x^3-7x+6
=(x^3-2x^2+x)+(2x^2-4x+2)+(-4x+4)
=x(x-1)(x-1)+2(x-1)(x-1)-4(x-1)
=(x-1)(x^2-x+2x-2-4)
=(x-1)(x^2+x-6)
=(x-1)(x-2)(x+3)

(ax+by)2次方-(bx-ay)2次方

(ax+by)^2-(bx-ay)^2
=(ax+by-bx+ay)(ax+by+bx-ay)

1.x^3-x-(6x-6)=x(x+1)(x-1)-6(x-1)=(x+1)(x-1)(x-6)
2.(ax+by)2次方-(bx-ay)2次方=(ax+by+bx-ay)(ax+by-bx+ay)

1.=x(3次方)-7x+27-21
=(x+3)(x平方-3x+9)-7(x+3)
=(x-3)(x平方+3x+2)
=(x-3)(x+1)(x+2)

2.(ax+by)2次方-(bx-ay)2次方=(ax+by+bx-ay)(ax+by-bx+ay)

一楼第一题错了!!!

(1)x^3-7x+6 = (x^3-x)-6(x-1)=x(x^2-1)-6(x-1)=x(x+1)(x-1)-6(x-1)=(x-1)(x^2+x-6)
(2)(ax+by)^2-(bx-ay)^2=(ax+by+bx-ay)(ax+by-bx+ay)

1.x^3-x-(6x-6)=x(x+1)(x-1)-6(x-1)=[x(x+1)-6](x-1)
=(x^2+x-6)(x-1)=(x+3)(x-2)(x-1)
2.(ax+by)2次方-(bx-ay)2次方=(ax+by+bx-ay)(ax+by-bx+ay)