物理化简 急 多加10分

来源:百度知道 编辑:UC知道 时间:2024/05/27 11:47:02
化简:y=1/2g(t+0.8)方-1/2gt方
然后 x=3.6m
代入 x方+y方=36
求出t
G取10

对于这个式子: y=1/2g(t+0.8)方-1/2gt方
先提出因子1/2g: =1/2g[(t+0.8)方-t方]
平方差公式分解: =1/2g(t+0.8-t)(t+0.8+t)
=1/2g*0.8*(2t+0.8)
代入值g=10,化简:=8t+3.2
现在就得到关系式:y=8t+3.2

因为:x方+y方=36(代入x=3.6, y=8t+3.2)
得到: 3.6方+(8t+3.2)方=36
(8t+3.2)方=36-3.6方
等式右边平方差分解:(8t+3.2)方=(6+3.6)(6-3.6)
(8t+3.2)方=9.6*2.4
(8t+3.2)方=4*2.4*2.4 (4*2.4=9.6)
开平方: 8t+3.2=2*2.4 (负值舍去,时间不能为负)
因此:8t=4.8-3.2=1.6,t=0.2(s)

t=0.2

x^2+y^2=36
3.6^2+y^2=36
y^2=4.8^2
y=4.8

y=1/2g(t+0.8)^2-1/2gt^2
=1/2g(t^2+1.6t+0.64)-1/2gt^2
=1/2g(1.6t+0.64)
=0.8gt+0.32g=4.8
8t+3.2=4.8
8t=1.6
t=0.2

t方-0.4t+1.04=0

y=gt^2/2+g*2*t*0.8/2+g*0.8^2/2-gt^2/2
=8t+3.2
3.6^2+(8t+3.2)^2=36
化简得t^2+0.8t-0.2=0
解得t=0.2s