解方程题，写过程

4(x-2)(x+5)-(2x-3)(2x+1)=5

4x^2+12x-40-[4x^2-4x-3]=5

16x=40+5-3

16x=42

x=21/8

12

解:
4(x^2+3x-10)-2(2x^2-5x-3)=5(打开括号)
4x^2+12x-40-4x^2+10x+6=5
22x=39(合并同类项)
x=39/22(系数化一)

4(x-2)(x+5)-(2x-3)(2x+1)=5
解:4(x^+3x-10)-(4x^-4x-3)-5=0
4x^+12x-40-4x^+4x+3-5=0
16x=42
x=2.625