高一数学 化简 三角函数

来源:百度知道 编辑:UC知道 时间:2024/06/07 08:10:38
(1) (sin α+cos α)^2;
(2) cos^4 θ-sin^4 θ;
(3) sin x cos x cos 2x;
(4) 1/(1-tan θ)-1/(1+tan θ).

(1) (sin α+cos α)^2
=sin α^2+cos α^2+2sin α*cos α
= 1+2sin2α

(2) cos^4 θ-sin^4 θ
=(cos^2 θ+sin^2 θ)(cos^2 θ-sin^2 θ)
=cos2θ

(3) sin x cos x cos 2x
=1/2(2sinxcosx)cos2x
=(1/4)2sin2xcos2x
= 1/4 sin4x

(4) 1/(1-tan θ)-1/(1+tan θ)
=2tanθ/(1-tan^2 θ)
=(2sinθ/cosθ)/(1-sin^2 θ/cos^2 θ)
=2sin2θ/(cos^2 θ-sin^2 θ)
=sin2θ/cos2θ
=tan2θ

(1) 1+2sin2α (二倍角公式)
(2) cos8θ (二倍角公式)
(3) 1/4 sin4x (二倍角公式)
(4) sin2θ (万能公式)