UC知道请能人指教！！如何能学好后台管理！！
来源：百度知道 编辑：UC知道 时间：2024/06/23 13:51:55
我现在在学习网站建设。可是我不会编程后台管理
例：<%
IsLogon = false
if session ("AuthCode") = "" then
IsLogon = false
else
AuthCodeArray = split(session ("AuthCode"),SplitCode)
UserName = strreverse(AuthCodeArray (0))
UserPwd = AuthCodeArray (2)
mykey = AuthCodeArray (3)
' if mykey <> request ("ce") then
' IsLogon = false
' else
set rs = conn.execute ("select * from Admin where UserName = '"& restr(UserName) &"' and PassWD = '"& restr(UserPwd) &"'")
if rs.eof and rs.bof then
IsLogon = false
else
keywords = "abcdefghijklmnopqrstuvwxyz1234567890~!@\_=-*?{}[]:"
mykey = ""
for i = 1 to 6
randomize
num1=rnd()
num1=int(50*num1)
if num1 <1 then
mykey = mykey & left(keywords,1)
elseif num1 > 49 then
m
例：<%
IsLogon = false
if session ("AuthCode") = "" then
IsLogon = false
else
AuthCodeArray = split(session ("AuthCode"),SplitCode)
UserName = strreverse(AuthCodeArray (0))
UserPwd = AuthCodeArray (2)
mykey = AuthCodeArray (3)
' if mykey <> request ("ce") then
' IsLogon = false
' else
set rs = conn.execute ("select * from Admin where UserName = '"& restr(UserName) &"' and PassWD = '"& restr(UserPwd) &"'")
if rs.eof and rs.bof then
IsLogon = false
else
keywords = "abcdefghijklmnopqrstuvwxyz1234567890~!@\_=-*?{}[]:"
mykey = ""
for i = 1 to 6
randomize
num1=rnd()
num1=int(50*num1)
if num1 <1 then
mykey = mykey & left(keywords,1)
elseif num1 > 49 then
m
这是一个权限判断程序
学会前台了，那么后台也就会了，程序代码是一个样的
作为编程就是两种结果，真和假
一般后台就是先判断是否合法管理员，是就让进，不是就退出
添加数据到数据库也是真和假，真值就是添加成功，假就是不成功
修改数据／删除数据都是如此
这里面无非主是些IF ELSE END IF等