1/(x-2)+2/(x+1)-2/(x-1)-1/(x+2)

来源：百度知道编辑：UC知道时间：2024/05/10 04:55:09

快!要步骤,好的话分加倍!
/前面是分子,/后是分母

1/(x-2)+2/(x+1)-2/(x-1)-1/(x+2)
=1/（x-2）+1/（x+1）+1/（x+1）-1/（x-1）-1/（x-1）-1/（x+2）
=[1/（x+1）-1/（x+2）]+[1/（x-2）-1/（x-1）]+[1/（x+1）-1/（x-1）]
=1/[（x+1）（x+2）]+1/[（x-2）（x-1）]-2/[（x+1）（x-1）]
=1/[（x+1）（x+2）]-1/[（x+1）（x-1）]+1/[（x-2）（x-1）]-1/[（x+1）（x-1）]
=-3/[（x+1）（x+2）（x-1）]+3/[（x-2）（x-1）（x+1）]
=12/[（x+1）（x+2）（x-1）（x-2）]

1/(x-2)+2/(x+1)-2/(x-1)-1/(x+2)
=[1/(x-2)-1/(x+2)]+[2/(x+1)-2/(x-1)]
=[(x+2-(x-2))/(x^2-4)]+[2(x-1-(x+1))/(x^2-1)]
=[4/(x^2-4)]+[-4/(x^2-1)]
=4((x^2-1)-(x^2-4))/(x^2-4)(x^2-1)
=12/(x^2-4)(x^2-1)
=12/(x-2)(x+2)(x-1)(x+1)

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