初二数学整式

肯定队哦

(1)16x*x-8xy+y*y
=(4x)(4x)-2*4x*y+y*y
=(4x-y)(4x-y)

(2)-(m-n)(m-n)+1=
=1^2-(m-n)(m-n)
=(1+m-n)(1-m+n)

(3)a(x*x-y*y)+b(y*y-x*x)=
=a(x+y)(x-y)+b(y+x)(y-x)
=a(x+y)(x-y)-b(x+y)(x-y)
=(x+y)(x-y)(a-b)

(4)4x*x*y*y(a+b)-2xy*y(a+b)=
=2xy*y(a+b)(2x-1)

(5)4(b-a)(b-a)(b-a)+2(a-b)(a-b)=
=4(a-b)(a-b)(b-a)+2(a-b)(a-b)
=(a-b)(a-b)[4(b-a)+2]

(6)-x*x*x*x+16y*y*y*y=
=(4y*y)*(4y*y) - (x*x)*(x*x)
=(4y*y+x*x)(4y*y-x*x)
=(x*x+4y*y)(2y+x)(2y-x)

因式分解
(1)16x*x-8xy+y*y= (4x-y)^2
(2)-(m-n)(m-n)+1= 1-(m-n)^2=(1+m-n)(1-m+n)
(3)a(x*x-y*y)+b(y*y-x*x)= a(x^2-y^2)-b(x^2-y^2)=(x^2-y^2)(a-b)=(x+y)(x-y)(a-b)
(4)4x*x*y*y(a+b)-2xy*y(a+b)= 2xy^2(a+b)(2x-1)
(5)4(b-a)(b-a)(b-a)+2(a-b)(a-b)= 4(b-a)^3+2(b-a)^2=(b-a)^2[4(b-a)+2]=(b-a)^2(4b-4a+2)
(6)-x*x*x*x+16y*y*y*y=(4y^2+x^2)(4y^2-x^2)=(4y^2+x^2)(2y+x)(2y-x)

(4x-y)*(4x-y)
第2个我看不明白啊
(a-