UC知道c++,递归函数,循环咋会无效???????
来源：百度知道 编辑：UC知道 时间：2024/05/16 20:45:38
题目是随机产生1到1000的数,让人猜,猜错了给出相应的提示,当输入'y'或'n'时,都不能循环!!!!!!!!!!!!!!!!!!!!!!
#include <iostream>
#include <stdlib.h>
using namespace std;
int a=0, b=0; bool c=true;
bool judge(int ){
if (b==a){
cout<<"Excellent you guessed the number!"<<endl;
cout<<"Would you like to play again (y or n )?";
if ('y'==cin.get())
return true;
else if('n'==cin.get())
return false;}
else if (b>a){
cout<<"Too high.Try again:";
cin>>b;
return judge(b);}
else if(b<a){
cout<<"Too low.Try again:";
cin>>b;
return judge(b);}}
int main(){
srand(time(NULL));
cout<<&
#include <iostream>
#include <stdlib.h>
using namespace std;
int a=0, b=0; bool c=true;
bool judge(int ){
if (b==a){
cout<<"Excellent you guessed the number!"<<endl;
cout<<"Would you like to play again (y or n )?";
if ('y'==cin.get())
return true;
else if('n'==cin.get())
return false;}
else if (b>a){
cout<<"Too high.Try again:";
cin>>b;
return judge(b);}
else if(b<a){
cout<<"Too low.Try again:";
cin>>b;
return judge(b);}}
int main(){
srand(time(NULL));
cout<<&
简单作些修改，供楼主参考。
另外，这个不需要递归，用循环就可以的
－－－－－－－－－－－－－－－－－－－－－－－－－
bool judge(int b)//这里是不是少了b?
{
if (b==a)
{
cout<<"Excellent you guessed the number!"<<endl;
cout<<"Would you like to play again (y or n )?";
//只需要输入一次，所以应该先输入再判断
char ch;
cin>>ch;
if ('y'==ch) return true;
else if('n'==ch) return false;
else return false;//如果不是'y'或者'n'，也退出
}
else if (b>a)
{
cout<<"Too high.Try again:";
cin>>b;
return judge(b);}
else if(b<a)
{
cout<<"Too low.Try again:";
cin>>b;
return judge(b);
}
}
原因出在srand(time(NULL))上,如果把这句屏蔽,可以循环,当然就不是随机了
不知道应该怎么修改,改好了再到这联系你
你那个循环是什么用的？
不用循环的~~