2个初2的因式分解，看不懂说，别不留言..（过程）

①a^(m+2)-a^m = a^m*(a^2-1)=a^m*(a-1)*(a+1)

②x^4-2x^2y^2+y^4=(x^2)^2+(y^2)^2-2*(x^2)*(y^2)=(x^2-y^2)^2=(x+y)^2*(x-y)^2

a^m(a+1)(a-1)

(x^2+y^2)(x+y)(x-y)

a^m+2-a^m
=a^m(a+1)(a-1)

x^4-2x^2y^2+y^4
=[(x^2-y^2)^2]
=[(x-y)(x+y)]^2

①a^(m+2)-a^m
=a^m(a^2-1)
=a^m(a+1)(a-1);

②x^4-2x^2y^2+y^4
=(x^2-y^2)^2
=[(x-y)(x+y)]^2
=(x-y)^2(x+y)^2.

1)2 (a^m-a^m=0)
2)(x^2)^2-2x^2y^2+(y^2)^2
=(x^2-y^2)^2
=(x+y)^2 (x-y)^2