七年级数学计算题

a+a^2=3可得a^2+1/a^2+2=(a+a^2)^2=9
a^2 / a^4+a^2+1 =a^2+1/a^2+1==(a+a^2)^2-1=8

a~2-3a+1=0

2~2=3a-1

a^2 / a^4+a^2+1 =1/(3a-1)+3a-1+1
=1/(3a-1)+3a

a+1\a=3,把两边同时平方得(a+1\a)^2=9,a^2+1\a^2+2=9,a^2+1\a^2=7
a^2 / a^4+a^2+1=a^-2 +a^2+1=a^2+1\a^2+1=7+1=8
这是八年吧