解方程(X-2)/(X+3)=1-(2X-13)/(X^2-9)
来源:百度知道 编辑:UC知道 时间:2024/05/09 18:00:44
(X+1)/(X-1)+ 4/(X^2-1)=1 1/(2-X)=1/(X-2) - (6-X)/(3X^2-12)
(X+1)/(X-1)+ 4/(X^2-1)=1 1/(2-X)=1/(X-2) - (6-X)/(3X^2-12)
[(X+1)^2+4]/(X^2-1)=1
X^2+2X+1+4=X^2-1
2X=-6
X=3
分式要检验
经检验,成立
1/(2-X)=1/(X-2) - (6-X)/(3X^2-12)
-1/(X-2)=1/(X-2) - (6-X)/[3(X+2)(X-2)]
-2/(X-2)=- (6-X)/[3(X+2)(X-2)]
2/(X-2)= (6-X)/[3(X+2)(X-2)]
6(X+2)(X-2)=(6-X)(X-2)
6X^2-24=-X^2+8X-12
7X^2-8X-12=0
X=2,X=-6/7
经检验,X=2是增根
X=-6/7
1
x=108.5
(X+1)/(X-1)+ 4/(X^2-1)=1
[(x+1)^2+4]/(x^2-1)=1
x^2+2x+1+4=x^2-1
2x=-6
x=-3
1/(2-X)=1/(X-2) - (6-X)/(3X^2-12)
1/(2-x)+1/(2-x)=-(6-x)/(3x^2-12)
2/(2-x)=-(6-x)/(3x^2-12)
2(3x^2-12)=(x-6)(2-x)
6x^2-24+x^2-8x+12=0
7x^2-8x-12=0
(7x+6)(x-2)=0
x=-6/7或x=2
分式方程问题:解方程:[x+1)/(x+2)]+[(x+6)/(x+7)]=[(x+2)/(x+3)]+[(x+5)/(x+6)]
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