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5m-5=2n+6 (1)
2m+2=3n-9 (2)

(1)*2
10m-10=4n+12 (3)
(2)*5
10m+10=15n-45 (4)
(4)-(3)
20=11n-57
11n=77
n=7

代回原式得
m=5

5m-5=2n+6
2m+2=3n-9
5m-2n=11 (1)
2m-3n=-11 (2)
(1)*3-(2)*2
15m-4m=33+22
11m=55
m=5
n=(5m-11)/2=7

5(m-1)=2(n+3) ------1式
2(m+1)=3(n-3) ------2式

1式乘以2 减去 2式乘以5 得

10(m-1) -10(m+1) = 4(n+3) -15(n-3)
-20 = -11n+57
n = 7

将n=7代入1式得,
m =5