UC知道因式分解两题
来源：百度知道 编辑：UC知道 时间：2024/06/03 17:24:26
（x+1）^2-(2-y)^2
x^5-16x
写解答过程
x^5-16x
写解答过程
解
（x+1）^2-(2-y)^2
=(x+1-2+y)(x+1+2-y)
=(x+y-1)(x-y+3)
x^5-16x
=x(x^4-16)
=x(x^2-4)(x^2+4)
=x(x-2)(x+2)(x^2+4)
1.=(x+1+2-y)(x+1-2+y)=(x-y+3)(x+y-1)
2.=x(x^4-16)=x(x^2+4)(x^2-4)=x(x^2+4)(x+2)(x-2)
（x+1）^2-(2-y)^2
=[(X+1)+(2-Y)][(X+1)-(2-Y)]
=(X-Y+3)(X+Y-1)
x^5-16x
=X(X^4-16)
=X(X^2+4)(X^2-4)
=X(X^2+4)(X+2)(X-2)
=(x+1+2-y)(x+1-2+y)=(x-y+3)(x+y-1)
(x+1）^2-(2-y)^2
=[(X+1)+(2-Y)][(X+1)-(2-Y)]
=(X-Y+3)(X+Y-1)
2.=x(x^4-16)=x(x^2+4)(x^2-4)=x(x^2+4)(x+2)(x-2)