谁会解x的平方-2x小于等于3大于等于1这个式子啊？谢啦！

x^2-2x<=3
x^2-2x-3<=0
(x-3)(x+1)<=0
所以：-1<=x<=3.....[1]

x^2-2x>=1
x^2-2x+1>=2
(x-1)^2>=2

x>=根号2+1，或x<=-根号2+1.....[2]

综上所述[1]，[2]，得：

根号2+1<=x<=3或-1<=x<=-根号2+1

1<=x^2-2x<=3
分开解
1<=x^2-2x
x^2-2x-1>=0
x>=1+√2,x<=1-√2

x^2-2x<=3
x^2-2x-3<=0
(x-3)(x+1)<=0
-1<=x<=3

两个同时满足
所以-1<=x<=1-√2,1+√2<=x<=3