(1+1\2)(1+1\4)(1+1\6)...(1+1\10)(1-1\3)(1-1\5)..(1-1\3)(1-1\10)
来源:百度知道 编辑:UC知道 时间:2024/06/04 18:23:42
(1+1\2)(1+1\4)(1+1\6)...(1+1\10)(1-1\3)(1-1\5)..(1-1\3)(1-1\10)
(1+1/2)×(1+1/4)×(1+1/6)×......(1+1/10)×(1-1/3)(1-1/5)×......×(1-1/9)
=3/2×5/4×7/6×9/8×11/10×2/3×4/5×6/7×8/9
=11/10
把每个括号里面的项直接加出来,直接相乘,应该会有很多分子分母相互消去了,你自己试试吧
题目貌似有问题
(1+1\2)(1+1\4)(1+1\6)...(1+1\10)(1-1\3)(1-1\5)..(1-1\3)(1-1\11)
=(1+1/2)(1-1/3)(1+1/4)(1-1/5)...(1+1/10)(1-1/11)
=3/2*2/3*5/4*4/5*...*11/10*10/11
=1
1
(1+1/2)=2/3 (1+1/4)=5/4 (1+1/6)=7/6 (1+1/10)=1 又1/10
(1-1/3)=2/3 (1-1/5)=4/5 (1-1/3)=2/3 (1-1/10)=9/10
1
(1-1\2004)(1-1\2003)(1-1\2002).........(1-1\3)(1-1\2)
(1+1\2)*(1+1\3)*(1+1\3)*(1+1\4)*......(1+1\20)
((1+1\2)(1+1\3)(1+1\4)(1+1\5)------(1+1\100))\(1-1\2)(1-1\3)(1-1\4)------(1-1\100)
((1+1\2)(1+1\3)(1+1\4)(1+1\5)------(1+1\100))\(1-1\2)(1-1\3)(1-1\4)------(1-1\100)等多少
(1\2+1\3+...+1\2006)(1+1\2+1\3+...+1\2005)-(1+1\2+1\3+...+1\2006)(1\2+1\3+...+1\2005)
1\2+1\4+1\8+...+1\256+1\512+1\1024=??
(1-1\2)+(1\2-1\3)+(1\3-1\4)+(1\4-1\5)+(1\5-1\6)+........(1\2005-1\2006
(1-1\2)+(1\2-1\3)+(1\3-1\4)+(1\4-1\5)+(1\5-1\6)+........(1\2005-1\20把括号变为绝对号咋么做06
[1+(-1\2)]+[1\2+(-1\3)]+[1\3+(-1\4)]+......[1\1999+(-1\2000)]
1+1\2+1\4+……