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来源:百度知道 编辑:UC知道 时间:2024/06/04 01:23:03
(x-4/x-5)-(x-5/x-6)=(x-6/x-7)-(x-7/x-8)求x?

(x-4/x-5)-(x-5/x-6)=(x-6/x-7)-(x-7/x-8)
两边通分,就得到

-1/((x-5)(x-6)) = -1/((x-7)(x-8))

所以(x-5)(x-6)=(x-7)(x-8)
所以 -11x+30=-15x+56
所以4x=26
x=13/2

6.5

我硬算得

你好!
(x-4/x-5)-(x-5/x-6)=(x-6/x-7)-(x-7/x-8)
(x-5+1/x-5)-(x-6+1/x-6)=(x-7+1/x-7)-(x-8+1/x-8)
1+1/(x-5)-1-1/(x-6)=1+1/(x-7)-1-1/(x-8)
1/(x-5)-1/(x-6)=1/(x-7)-1/(x-8)
(x-6-x+5)/(x-5)(x-6)=(x-8-x+7)/(x-7)(x-8)
1/(x-5)(x-6)=1/(x-7)(x-8)
x^2-11x+30=x^2-15x+56
4x=26
x=6.5
是不是有点乱