一道数学计算题!!急急急!!

来源:百度知道 编辑:UC知道 时间:2024/05/31 17:27:03
(1/2005-1)×(1/2004-1)×......(1/3-1)×(1/2-1)

=(-2004/2005)×(-2003/2004)×......(-2/3)×(-1/2)
=1/2005 //一共有2004个负号!故结果为正!

1/2005

(1/2005-1)×(1/2004-1)×......(1/3-1)×(1/2-1)
=-2004/2005*-2003/2004*.......-1/2
=2004/2005*1/2
=1002/2005

(1/2005-1)×(1/2004-1)×......(1/3-1)×(1/2-1)
=(-1)^2004* 2004/2005*2003/2004*....*1/2
=1/2005

(1/2005-1)×(1/2004-1)×......(1/3-1)×(1/2-1)
=(-2004/2005)*(-2003/2004)*......(-2/3)*(-1/2)从2到2005一共是2005-2+1=2004是双数,所以
=(2004/2005)*(2003/2004))*......(2/3)*(1/2)
=1/2005