帮我解答两道数学题

1.(x^2-9)[1/(x+3)-1/(x-3)-1]
=(x+3)(x-3)[1/(x+3)-1/(x-3)-1]
=(x+3)(x-3)*1/(x+3)-(x+3)(x-3)*1/(x-3)-(x+3)(x-3)*1
=(x-3)-(x+3)-(x+3)(x-3)
=x-3-x-3-x^2+9
=-x^2+3

2.[1-1/(1-a^2)]÷[(a^2+2a)/(a^2-2a+1)]
=[1+1/(a^2-1)]×[(a^2-2a+1)/(a^2+2a)]
=[(a^2-1+1)/(a^2-1)]×[(a^2-2a+1)/(a^2+2a)]
=[a^2/(a^2-1)]×[(a^2-2a+1)/(a^2+2a)]
=a^2(a^2-2a+1)/[(a^2-1)(a^2+2a)]
=a^2(a-1)^2/[(a+1)(a-1)a(a+2)]
=a(a-1)/[(a+1)(a+2)]

1。（X-3)(X+3）(1/x+3 - 1/x-3 -1)
=X-3-(X-3)-X方-9
=-X方-9
2。(1- 1/1-a方）乘 （a方-2a+1/a方+2a）
=-a方 乘（ a-1）方/ a（a+2）
=-a（a-1）方/a+2
最后一步把括号拆了 你自己会吧 我打太麻烦了

靠