(根号6+根号2)/(根号6-根号2)
来源:百度知道 编辑:UC知道 时间:2024/06/13 22:14:39
谢谢 回答得详细点
(根号6+根号2)/(根号6-根号2)
=(根号6+根号2)^2/(根号6-根号2)(根号6+根号2)
=(8+4√3)/(6-2)
=2+√3
(√6+√2)/(√6-√2)
=[(√6+√2)×(√6+√2)]/[(√6-√2)(√6+√2)]
=(6+2√12+2)/(6-2)
=(8+4√3)/4
=2+√3
同时X(根号6+根号2)分母有理化 下面就是4了上面也算的出来
(根号6+根号2)/(根号6-根号2)
=(6^1/2+2^1/2)^2/((6^1/2-2^1/2)(6^1/2+2^1/2))
=(6+2*12^1/2)/(6-2)
=(8+4*3^1/2)/4
=2+3^1/2
=2+1.73=3.73
给分子分母同乘以(根号6+根号2)
使分母有理化
得(根号6+根号2)^/4
解:(根号6+根号2)/(根号6-根号2)
=(根号6+根号2)*(根号6+根号2)/(根号6-根号2)*(根号6+根号2)
=(6+2+4根号3)/4
=2+根号3