初一数学~帮帮忙

解:已知a,b互为相反数，c,d互为负倒数，|m|=4
则a+b=0，cd=-1,m²=16
所以5a-6m2次方+5b-(cd)2007次方
=5(a+b)-6 m²-(cd)2007次方
=5•0-6•16-(-1)2007次方
=-96-(-1)
=-95

ab互为相反数，a+b=0
c,d互为倒数，ab=1
5a-6m^2+5b-(cd)^2007
=5(a+b)-6m^2-(cd)^2007
=0-96-1
=-97

a+b=0
5a+5b=0
c*d=-1
m^2=(m)^2, (-m)^2
=-6*16+1
=-95