UC知道c语言打印输出的延迟
来源：百度知道 编辑：UC知道 时间：2024/04/29 22:36:47
main()
{
int i;
for(i=1;i<=999;i++)
{
printf("\n");
printf(" 00 000000000000 00 00 00000000000000 0000\n");
printf(" 00 00 00 00 00 00000000 00 0000\n");
printf(" 00000000000 00 00 000 00 00 00 00 0000\n");
printf("00 00 000000000000 00000 000000000 00000000000000 0000\n");
printf(" 0000000000 00 00 0 00 0 00 00 0000\n");
printf(" 00 00 00 00 00 00 00 0 00 00\n");
printf("00000000000000 000000000000 00 00 00 00 0000 00 00\n");
printf("\n\n\n\n\n\n\n\n\n\n");
}
}
==============================================
{
int i;
for(i=1;i<=999;i++)
{
printf("\n");
printf(" 00 000000000000 00 00 00000000000000 0000\n");
printf(" 00 00 00 00 00 00000000 00 0000\n");
printf(" 00000000000 00 00 000 00 00 00 00 0000\n");
printf("00 00 000000000000 00000 000000000 00000000000000 0000\n");
printf(" 0000000000 00 00 0 00 0 00 00 0000\n");
printf(" 00 00 00 00 00 00 00 0 00 00\n");
printf("00000000000000 000000000000 00 00 00 00 0000 00 00\n");
printf("\n\n\n\n\n\n\n\n\n\n");
}
}
==============================================
在每个打印语句之后做一个for循环，循环一个100,000次就应该差不多了
如果不够，循环次数再加，呵呵不过要用long int就好了
从下到上，就把语句反过来写就是啦
不过实在不明白卫生要打印这个东东999次？