三道初一的数学题～关于因式分解（急求！）

1） 4a^2+2a-b-b^2
=(4a^2-b^2)+(2a-b)
=(2a-b)(2a+b)+(2a-b)
=(2a-b)(2a+b+1)

2) 2pq-p^2+1-q^2
=1-(p^2-2pq+q^2)
=1-(p-q)^2
=(1+p-q)(1-p+q)

3) x^2+2xy+y^2-3x-3y+2
=(x+y)^2-3(x+y)+2
=(x+y-1)(x+y-2)

4a²-2a-b-b²
=(4a²-2a+1/4)-(b²+b+1/4)
=(2a-1/2)²-(b+1/2)²
=[(2a-1/2)+(b+1/2)][(2a-1/2)-(b+1/2)]
=(2a+b)(2a-b-1)

2pq-p²+1-q²
=1-(p²-2pq+q²)
=1²-(p-q)²
=[1+(p-q)][1-(p-q)]
=(1+p-q)(1-p+q)

x²+2xy+y²-3x-3y+2
=(x²+2xy+y²)-3(x+y)+2
=(x+y)²-3(x+y)+2
=[(x+y)-1][(x+y)-2]
=(x+y-1)(x+y-2)

1） 4a^2+2a-b-b^2
=(2a+b)(2a-b)+(2a-b)
=(2a-b)(2a+b-1)

2) 2pq-p^2+1-q^2
=-(p^2-2pq+q^2)+1
=-(p-q)^2+1
=1-(p-q)^2
=(1+p-q)(1-p+q)

3) x^2+2xy+y^2-3x-3y+2
=(x+y)^2-3(x+y)+2
=(x=y-2)(x+y-1)

1） 4a^2+2a-b-b^2
=(4a