两个初中整式乘法的问题

1. (a+b)^2=a*a+b*b+2ab=a*a+b*b+2*1=3^2
a*a+b*b的值为9-2=7

2. (a+b)^2-(a*a+b*b)=2ab=16-4=12
ab=6
a*a*b*b的值为6^2=36

1,(a+b)^2=9
a*a+b*b=9-2=7
2,(a+b)^2=16
a*a*b*b=[(16-4)/2]^2=36

1.已知a+b=3,ab=1,a*a+b*b=(a+b)^2-2ab=3^2-2*1=7

2.如果a*a+b*b=4,a+b=4,(a+b)^2-(a*a+b*b)=4^2-4,即2ab=12,ab=6,a*a*b*b=(ab)^2=6^2=36

^2 是平方的意思

1.(a+b)^2=9
(a+b)^2=a*a+b*b+2ab=9
ab=1
aa+bb+2=9
aa+bb=7
2.aa+bb+2ab=(a+b)^2
4+2ab=16
2ab=12
ab=6
(ab)^2=36
aabb=36