若xy互为相反数,求x+2x+3x+...+100x+100y+99y+98y+,,,+2y+y的值

因为x,y互为相反数x+y=0

x+2x+3x+...+100x+100y+99y+98y+,,,+2y+y

=(x+y)+2(x+y)+3(x+y)+...+100(x+y)
=0

=0啊
很简单啊
原式=X+Y+2X+2Y+3X+3Y+...+100X+100Y
=1*(X+Y)+2(X+Y)+...+100(X+Y)
因为（x+y)=0
所以原式=0

若xy互为相反数,求x+2x+3x+...+100x+100y+99y+98y+,,,+2y+y的值

x,y互为相反数x+y=0

x+2x+3x+```+100x+100y+99y+98y+```+2y+y

=(x+y)+2(x+y)+3(x+y)+...+100(x+y)
=0

=0.
假设x=y=0。