数学初二计算!

原式=[(x+y)^3*(x-y)^3/(x^2+y^2)]*[(x^2+y^2)^2*(x+y)^2*(x-y)^2]/(x+y)^4
=(x-y)^3*(x+y)*(x-y)^2
=(x+y)(x-y)^5

原式=（x^2+y^2）^3分之（x^2-y^2）^3*（x+y）^4分之（x^2+y^2）^2（x^2-y^2）^2
=（x^2+y^2）（x+y）^4分之（x+y）^3（x-y）^3（x+y）^2（x-y）^2
=x^2+y^2分之（x-y）^5（x+y）

[(x^2-y^2)/(x^2+y^2)]^3÷[(x^2+2xy+y^2)/(x^4-y^4)]^2
=[(x^2-y^2)^3/(x^2+y^2)^3]÷[(x+y)^4/(x^2+y^2)^2(x^2-y^2)^2]
=(x^2-y^2)^3(x^2+y^2)^2(x^2-y^2)^2/[(x^2+y^2)^3(x+y)^4]
=(x^2-y^2)^5/(x+y)^4
=(x+y)^5(x-y)^5/(x+y)^4
=(x+y)(x-y)^5