数学代数!!!!!

令X-Y=a,Z-X=b
则a+b=X-Y+Z-X=Z-Y
所以上式可化为：
（a+b）^2-4ab=0化成（a-b）^2=0
所以有a=b
所以Z-X/X-Y=a/b=1

33333

(Y—Z)^2-4(X-Y)(Z-X)=0
[(x-y)+(z-x)]^2-4(x-y)(z-x)=0
(x-y)^2-2(x-y)(z-x)+(z-x)^2=0
[(x-y)-(z-x)]^2=0
x-y=z-x
(Z-X)/(X-Y)=1

(y-z)^2-4(x-y)(z-x)=0
化简得(2x-y-z)^2=0
则2x-y-z=0
x-y=z-x
所以(z-x)/(x-y)=1