若6x/（xx-9）=A/（x+3）+B/（x-3），则A=(),B=()

6x/(xx-9)=A/(x+3)+B/(x-3)
6x/(xx-9)=A(x-3)/(x+3)(x-3)+B(x+3)/(x+3)(x-3)
6x/(xx-9)=[A(x-3)+B(x+3)]/(xx-9)
6x/(xx-9)=(Ax-3A+Bx+3B)/(xx-9)
6x=(A+B)x-3A+3B
得出,
A+B=6
B-A=0
解得,
A=3,B=3

这个问题是高考题吧，真难……我试了一天A=B=3 …

A=3,B=3