已知xx yy 2x-6y 10=0求x,y的值

x^2+y^2+2x-6y+10=0
x^2+2x+1+y^2-6y+9=0
(x+1)^2+(y-3)^2=0
x+1=0 x=-1
y-3=0 y=3

xx+yy+2x-6y+10=0
xx+2x+1 +yy-6y+9 =0
(x+1)*(x+1) +(y-3)*(y-3)=0

要使等式成立,必须
x+1=0 且y-3=0
x= -1, y= 3.

xx+yy+2x+6y+10=xx+2x+1+yy-6y+9=(x+1)(x+1)+(y-3)(y-3)=0,
只有(x+1)(x+1)和(y-3)(y-3)同时等于0才能成立,否则大于0,所以,只有小x=-1；y=3.

xx+yy+2x-6y+10
=xx+yy+2x-6y+1+9
=xx+2x+1+yy-6y+9
=(x+1)(x+1)+(y-3)(y-3)
=0
所以x+1=0,解得x=-1
y-3=0,解得y=3

不难啊

简单啊楼上的答案都对啊x=-1,y=3