UC知道有两道数学因式分解怎么写啊
来源：百度知道 编辑：UC知道 时间：2024/06/08 15:53:30
2（x+Y)^2-20(x+y)+50 和(ax+by)-2acxz-2bcyz+c^2z^2 就两题要有过程麻烦了谢谢
2（x+Y)^2-20(x+y)+50
=2[(x+y)^2-10(x+y)+25]
=2(x+y-5)^2
(ax+by)^2-2acxz-2bcyz+c^2z^2
=(ax+by)^2-2cz(ax+by)+c^2z^2
=(ax+by-cz)^2
2(x+y)^2-20(x+y)+50=2(x+y+5)^2
(ax+by)-2acxz-2bcyz+c^2z^2
=(ax+by)-2cz(ax+by)+c^2z^2
=(ax+by-cz)^2
2（x+Y)^2-20(x+y)+50 =(2x+2y-10)(x+y-5)=2(x+y-5)^2
(ax+by)-2acxz-2bcyz+c^2z^2 题目你好好看看，这个分解不了！
1. 2（x+Y)^2-20(x+y)+50
=2[(x+y)^2-10(x+y)+25]
=2[(x+y)-5^2]
=2(x+y-5)^2
2. (ax+by)^2-2acxz-2bcyz+c^2z^2
=(ax+by)^2-2cz(ax+by)+c^2z^2
=(ax+by-cz)^2
2（x+Y)^2-20(x+y)+50
=2[(x+y)^2-10(x+y)+25]
=2(x+y-5)^2
2(X+Y-5)^2
(ax+by-cz)^2