(1+2)(1+4)(1+16)x...x(1+2^32)
来源:百度知道 编辑:UC知道 时间:2024/09/24 00:56:33
(2+1)*(4+1)*(16+1)*(256+1)
1,1,8,16,7,21,4,16,2,( )
化简(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
化简:(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16)
计算:3*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
计算:2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)+1
2分之1-4分之1-8分之1-16分之1-64分之1=
(3+1)(3^2+1)(3^4+1)(3^16+1)(3^32+1)
(2^1+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)等于多少?
试确定(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1的末位数字