UC知道数学难题求解····
来源：百度知道 编辑：UC知道 时间：2024/06/21 02:22:13
附题目[(1/2)+(1/3)+(1/4)+......+(1/2010)]*[1+(1/2)+(1/3)+......+(1/2009)]-[1+(1/2)+(1/3)+(1/4)+......+(1/2010)][(1/2)+(1/3)+(1/4)+......(1/2009)]
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[(1/2)+(1/3)+(1/4)+......+(1/2010)]*[1+(1/2)+(1/3)+......+(1/2009)]-[1+(1/2)+(1/3)+(1/4)+......+(1/2010)][(1/2)+(1/3)+(1/4)+......(1/2009)]
=[(1/2)+(1/3)+(1/4)+......+(1/2010)]*{[1+(1/2)+(1/3)+......+(1/2009)]-[1+(1/2)+(1/3)+......+(1/2009)]}
=[(1/2)+(1/3)+(1/4)+......+(1/2010)]*(1-1+(1/2)-(1/2)+(1/3)-(1/3)+...+......+(1/2009)-(1/2009)
=[(1/2)+(1/3)+(1/4)+......+(1/2010)]*(0)
=0
设[(1/2)+(1/3)+(1/4)