若sinx+cosx=1/5,且0<x<∏,则x是第几象限角,sinx=?,cosx=?,tanx=?(请写过程)

sinx+cosx=1/5....................................(1)
(sinx+cosx)平方=1/25
1+2sinx*cosx=1/25
2sinx*cosx=-24/25
sinx*cosx-12/25..................................(2)
∵0<x<∏,sinx>0,∴cosx<0,∴π/2<x<π,x是第二象限角
(sinx-cosx)平方=1-2sinx*cosx=49/25
sinx-cosx>0
∴sinx-cosx=7/5..................................(3)
(1)+(3):2sinx=8/5,sinx=4/5
(1)-(3):2c0sx=-6/5,cosx=-3/5
tanx=sinx/cosx=-4/3