一道很容易的分解因式题 谢谢了

来源：百度知道 编辑：UC知道 时间：2024/05/25 01:47:52
(x-y)(3x+y)^2+(x+3y)^2*(y-x)
要过程..

(x-y)(3x+y)^2+(x+3y)^2*(y-x)
=(x-y)[(3x+y)^2-(x+3y)^2]
=(x-y)[9x^2+6xy+y^2-(x^2+6xy+9y^2)]
=(x-y)(8x^2-8y^2)
=8(x-y)^2(x+y)

原式=(x-y)[(3x+y)^2-(x+3y)^2]
=(x-y)[9x^2+6xy+y^2-(x^2+6xy+9y^2)]
=(x-y)[8x^2-8y^2]
=8(x-y)(x-y)(x+y)
=8(x-y)^2(x+y)

(x-y)(3x+y)^2+(x+3y)^2*(y-x)

=(x-y)((3x+y)^2-(x+3y)^2))

(x-y)(4x+4y)(2x-2y)

有不懂发消息问我.

（x-y)(3x+y)^2+(x+3y)^2*(y-x)
=（x-y)(3x+y)^2-(x+3y)^2*(x-y)
=(x-y)[(3x+y)^2-(x+3y)^2]
=(x-y)(8x^2-8y^2)
=8(x-y)(x^2-y^2)
=8(x-y)(x+y)(x-y)
=8(x-y)^2(x+y)