2(x+3)/5=3/2-2(x-7)/3
来源:百度知道 编辑:UC知道 时间:2024/06/06 11:41:58
解x,最好有过程
解:2(x+3)/5=3/2-2(x-7)/3
2*6(x+3)/30=3*15/30-2*10(x-7)/30
12x+36=45-20x+140
32x=149
x=149/32
两边同乘30
6*2(x+3)=15*3-10*2(x-7)
12x+36=45-20x+140
32x=149
x=149/32
原方程式等于
12(x+3)=45-20(x-7)
12x+36=45-20x+140
32x=149
x=149/32
(2x+6)/5=3/2-(2x-14)/3
12x+36=45-20x+140
32x=149
12x+18=45-20x+140
32x=167
x=32/167
2(x+3)/5=3/2-2(x-7)/3
3*2(x+3)=15*3/2-5(x-7)
6x+18=22.5-5x+35
11x=75.5-18
11x=39.5
x=39.5/11
x+x^2+x^3+x^4+x^5+...+x^12=500/12
(x-4)(x-2)-(x-1)(x+3),其中x=-2/5
(5/(X-1)(X+2))+(3/(X+2)(X+3))=2/(X-1)(X-3)
(X+2)(X+3)(X-4)(X-5)=144
方程(x+1/x+2)+(x+2/x+3)=(x+3/x+4)+(x+4/x+5)的解
x+2/x+1-x+3/x+2=x+4/x+3-x+5/x+4
x^2-3x+1=0,求2x^5-5x^4-x^3+x^2-6x/x^2+1
(x+2/x+1)+ (x+6/x+5)=(x+3/x+2)+(x+5/x+4)怎么解?
x-5/x-7+x-2/x--4=x-3/x-5+x-4/x-6
分式方程问题:解方程:[x+1)/(x+2)]+[(x+6)/(x+7)]=[(x+2)/(x+3)]+[(x+5)/(x+6)]